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Given : (i) Cu^2++2 e^- → Cu_, E°=0.337 ~V (i) Cu^2++ e^- → Cu^+, E°=0.153 ~V Electrode potential E° for the reaction, Cu^++ e^- → Cu, will be :

NEET UG 2009 — Chemistry Physical Chemistry

2009mcqhard

Given : (i) Cu2++2e−→Cu,E∘=0.337 V\mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}_{,} \mathrm{E}^{\circ}=0.337 \mathrm{~V}Cu2++2e−→Cu,​E∘=0.337 V (i) Cu2++e−→Cu+,E∘=0.153 V\mathrm{Cu}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}^{+}, \mathrm{E}^{\circ}=0.153 \mathrm{~V}Cu2++e−→Cu+,E∘=0.153 V Electrode potential E∘\mathrm{E}^{\circ}E∘ for the reaction, Cu++e−→Cu\mathrm{Cu}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}Cu++e−→Cu, will be :

Official previous-year question

Held on 30 Apr 2009 · Verified 9 Jul 2026.

Options

  1. A

    0.38 V0.38 \mathrm{~V}0.38 V

  2. B

    0.52 V0.52 \mathrm{~V}0.52 V

  3. C

    0.90 V0.90 \mathrm{~V}0.90 V

  4. D

    0.30 V0.30 \mathrm{~V}0.30 V

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