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For the reaction, N_2+3 H_2 → 2 NH_3, If d [ NH_3 ] dt=2 × 10^-4 ~mol ~L^-1 ~s^-1, The value of - d [ H_2 ] dt would be -

NEET UG 2009 — Chemistry Physical Chemistry

2009mcqmedium

For the reaction, N2+3H2→2NH3\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3N2​+3H2​→2NH3​, If d[NH3]dt=2×10−4 mol L−1 s−1\frac{\mathrm{d}\left[\mathrm{NH}_3\right]}{\mathrm{dt}}=2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}dtd[NH3​]​=2×10−4 mol L−1 s−1, The value of −d[H2]dt\frac{-\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}dt−d[H2​]​ would be -

Official previous-year question

Held on 30 Apr 2009 · Verified 9 Jul 2026.

Options

  1. A

    1×10−4 mol L−1 s−11 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}1×10−4 mol L−1 s−1

  2. B

    3×10−4 mol L−1 s−13 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}3×10−4 mol L−1 s−1

  3. C

    4×10−4 mol L−1 s−14 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}4×10−4 mol L−1 s−1

  4. D

    6×10−4 mol L−1 s−16 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}6×10−4 mol L−1 s−1

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