31dt−d[H2]=21dt[NH3]dt−d[H2]=23dtd[NH3]dt−d[H2]=23×2×10−4=3×10−4 mol L−1 s−1
NEET UG 2009 — Chemistry Physical Chemistry
For the reaction, N2+3H2→2NH3, If dtd[NH3]=2×10−4 mol L−1 s−1, The value of dt−d[H2] would be -
Held on 30 Apr 2009 · Verified 9 Jul 2026.
1×10−4 mol L−1 s−1
3×10−4 mol L−1 s−1
4×10−4 mol L−1 s−1
6×10−4 mol L−1 s−1
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