Given, N2+3H2⇌2NH3;K1 N2+O2⇌2NO;K2H2+21O2⇌H2O;K3 We have to calculate 4NH3+5O2⟶4NO+6H2O;K= ? or 2NH3+25O2⟶2NO+3H2O For this equation K=[NH3]2[O2]5/2[NO]2[H2O]3 but K1 K2K3 K3=[ N2][H2]3[NH3]2=[ N2][O2][NO]2=[H2][O2]1/2[H2O]=[H2]3[O2]3/2[H2O3 Now K1K2⋅K33=[ N2][O2][NO]2×[H2]3[O2]3/2[H2O]3×[NH3]2[N2][H2]3=[NH3]2[O2]5/2[NO]2[H2O]3=K∴K= K1K2⋅K33