For the reaction Br2(l)+Cl2(g)→2BrCl(g)ΔH=30 kJ/molΔS=105JK−1 mol−1 For at equilibrium ΔG=0 ∴ΔG=ΔH−TΔSΔH=TΔST=ΔSΔH=105JK−1 mol−130×1000 J mol−1=285.7 K
The enthalpy and entropy change for the reaction: Br2(l)+Cl2(g)→2BrCl(g) are 30 kJ mol−1 and 105 J K−1 mol−1 respectively. The temperature which the reaction will be in equilibrium is:
Held on 30 Apr 2006 · Verified 9 Jul 2026.
300 K
285.5 K
273 K
450 K
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