Δx=0.1A˚=0.1×10−10 m m=9.11×10−31 kg h=6.626×10−34Js In uncertain position, Δv×Δx=4πmhΔv×0.1×10−10=4×3.14×9.11×10−316.626×10−34Δv=4×3.14×9.11×10−31×0.1×10−106.626×10−34=5.785×106 ms−1
Given: The mass of electron is 9.11 × 10^-31 ~kg, Planck constant is 6.626 × 10^-34 Js. The uncertainty involved in the measurement of velocity…
NEET UG 2006 — Chemistry Physical Chemistry
2006mcqhard
Given: The mass of electron is 9.11× 10−31 kg, Planck constant is 6.626× 10−34Js. The uncertainty involved in the measurement of velocity within a distance of 0.1A˚ is:
Official previous-year question
Held on 30 Apr 2006 · Verified 9 Jul 2026.
Options
- A
5.79×105 ms−1
- B
5.79×106 ms−1
- C
5.79×107 ms−1
- D
5.79×108 ms−1
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