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Consider the reaction: N_2(g)+3 H_2(g) → 2 NH_3(g) The equality relationship between d [ NH_3 ] d t and - d [ H_2 ] d t is:

NEET UG 2006 — Chemistry Physical Chemistry

2006mcqmedium

Consider the reaction: N2(g)+3H2(g)→\mathrm{N}_{2(g)}+3 \mathrm{H}_{2(g)} \rightarrowN2(g)​+3H2(g)​→ 2NH3(g)2 \mathrm{NH}_{3(g)}2NH3(g)​ The equality relationship between d[NH3]dt\frac{d\left[\mathrm{NH}_3\right]}{d t}dtd[NH3​]​ and −d[H2]dt-\frac{d\left[\mathrm{H}_2\right]}{d t}−dtd[H2​]​ is:

Official previous-year question

Held on 30 Apr 2006 · Verified 9 Jul 2026.

Options

  1. A

    d[NH3]dt=−d[H2]dt\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{d\left[\mathrm{H}_2\right]}{d t}dtd[NH3​]​=−dtd[H2​]​

  2. B

    d[NH3]dt=−13d[H2]dt\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{1}{3} \frac{d\left[\mathrm{H}_2\right]}{d t}dtd[NH3​]​=−31​dtd[H2​]​

  3. C

    +d[NH]3dt=−23d[H2]dt+\frac{d[\mathrm{NH}]_3}{d t}=-\frac{2}{3} \frac{d\left[\mathrm{H}_2\right]}{d t}+dtd[NH]3​​=−32​dtd[H2​]​

  4. D

    +d[NH3]dt=−32d[H2]dt+\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{3}{2} \frac{d\left[\mathrm{H}_2\right]}{d t}+dtd[NH3​]​=−23​dtd[H2​]​

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