Work =−Pext× volume change =3×101.32×(6−4)=6×101.32=−607.92 J=−608 J
The work done during expansion of a gas from a volume of 4 dm^3 to 6 dm^3 against a constant external pressure of 3 ~atm is (1 ~L ~atm=101.32 ~J) :
NEET UG 2004 — Chemistry Physical Chemistry
The work done during expansion of a gas from a volume of 4dm3 to 6dm3 against a constant external pressure of 3 atm is (1 L atm=101.32 J) :
Held on 30 Apr 2004 · Verified 9 Jul 2026.
Options
- A
−6 J
- B
−608 J
- C
+304 J
- D
−304 J
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