Ksp=3.2×10−11AX2⇌A2++2X−S2 S Ksp=S×(2 S)2=4 S3;=3.2×10−11=4 S3 or, S3=0.8×10−11=8×10−12 ∴S=2×10−4. Related Theory The solubility of a substance in a solvent is the total amount of the solute that can be dissolved in the solvent at equilibrium. On the other hand, the solubility product constant is an equilibrium constant that provides insight into the equilibrium between the solid solute and its constituent ions that are dissociated across the solution.
The solubility product of a sparingly soluble salt AX_2 is 3.2 × 10^-11. Its solubility (in moles/litre) is:
NEET UG 2004 — Chemistry Physical Chemistry
2004mcqmedium
The solubility product of a sparingly soluble salt AX2 is 3.2×10−11. Its solubility (in moles/litre) is:
Official previous-year question
Held on 30 Apr 2004 · Verified 9 Jul 2026.
Options
- A
5.6×10−6
- B
3.1×10−4
- C
2×10−4
- D
4×10−4
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