Molar heat capacity =75 J K−1 mol−1 18 g of water =1 mole =75 J K−1 mol−11 g of water =1875JK−1Q= m.c. Δt 1000⇒Δt=100×1875×Δt=7510×18=2.4 K
NEET UG 2003 — Chemistry Physical Chemistry
The molar heat capacity of water at constant, pressure, C, is 75 J K−1 mol−1. When 1.0 kJ of heat is supplied to 100 g of water which is free to expand, the increase in temperature of water is:
Held on 30 Apr 2003 · Verified 9 Jul 2026.
1.2 K
2.4 K
4.8 K
6.6 K
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