Skip to main content

The e.m.f. of a Deniell cell at 298 ~K is E_1 Zn | … | Cu When the concentration of ZnSO_4 in 1.0 M and that of CuSO_4 is 0.01 M, the e.m.f. changed…

NEET UG 2003 — Chemistry Physical Chemistry

2003mcqmedium

The e.m.f. of a Deniell cell at 298 K298 \mathrm{~K}298 K is E1\mathrm{E}_1E1​ Zn∣ZnSO4(0.01M)∣∣CuSO4(0.01M)∣Cu\mathrm{Zn}\left|\begin{array}{c} \mathrm{ZnSO}_4 \\ (0.01 \mathrm{M}) \end{array}\right|\left|\begin{array}{c} \mathrm{CuSO}_4 \\ (0.01 \mathrm{M}) \end{array}\right| \mathrm{Cu}Zn​ZnSO4​(0.01M)​​​CuSO4​(0.01M)​​Cu When the concentration of ZnSO4\mathrm{ZnSO}_4ZnSO4​ in 1.0 M\mathrm{M}M and that of CuSO4\mathrm{CuSO}_4CuSO4​ is 0.01M0.01 \mathrm{M}0.01M, the e.m.f. changed to E2\mathrm{E}_2E2​. What is the relationship between E1E_1E1​ and E2E_2E2​ ?

Official previous-year question

Held on 30 Apr 2003 · Verified 9 Jul 2026.

Options

  1. A

    E1>E2\mathrm{E}_1>\mathrm{E}_2E1​>E2​

  2. B

    E1<E2\mathrm{E}_1 < \mathrm{E}_2E1​<E2​

  3. C

    E1=E2\mathrm{E}_1=\mathrm{E}_2E1​=E2​

  4. D

    E2=0≠E1\mathrm{E}_2=0 \neq \mathrm{E}_1E2​=0=E1​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

NEET UG Physical Chemistry in other years

More NEET UG Physical Chemistry questions

Other Chemistry topics for NEET UG

Keep practicing Physical Chemistry

Work through every NEET UG Physical Chemistry PYQ, year by year.

Browse all Chemistry topics