2.5 L 1M Naoh with 3 L 0.5M NaOH. Intially, Number of moles in 2.5 L, 1MNaOH=2.5×1=2.5 moles Number of moles in 3 L,0.5MNaOH =3×0.5=1.5 moles. ⇒ Total number of moles in final mixture =2.5+1.5=4.0 moles . The total volume of solution =2.5+3=5.5 L ⇒ Molarity of final solution =5.54=0.728M
5 ~L of 1 M NaOH solution is mixed with 3 ~L of 0.5 M NaOH solution. Find out the molarity of the resultant solution:
NEET UG 2002 — Chemistry Physical Chemistry
5 L of 1MNaOH solution is mixed with 3 L of 0.5MNaOH solution. Find out the molarity of the resultant solution:
Held on 30 Apr 2002 · Verified 9 Jul 2026.
Options
- A
0.80M
- B
1.0M
- C
0.73M
- D
0.50M
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