Sodium chloride in water dissociates as: NaClH2O⇌Na++Cl−⇌H+OH− When electric current is passed through this solution using platinum electrodes. Na+and H+move towards cathode whereas Cl−and OH−ions move towards anode. At cathode H++e−H+H→H→H2 An anode Cl−Cl+Cl→Cl+e−→Cl2 If mercury is used as cathode H+ ions are not discharged at mercury cathode because mercury has a high hydrogen over voltage. Na+ ions are dischaged at cathode in preference of H+ions yielding sodium, which dissolves in mercury to form amalgam