(i) C(s)+O2( g)→CO2(g); ΔHi=−94kcal/mole (ii) 2H2(g)+O2(g)→2H2O(l); ΔHii=−68×2kcal/mole (iii) CH4(g)+2O2(g)→CO2(g)+ 2H2O(l);ΔHiii=−213kcal/mol (iv) C(s)+2H2(g)→CH4( g); ΔHIV= ? By applying Hess's law we can compute ΔHiv. ∴ΔHiv=ΔHi+ΔHii−ΔHiii=(−94−68×2+213)kcal=−17kcal