The correct order of the… - NEET UG 2017 Chemistry PYQ

NEET UG 2017 — Chemistry Inorganic Chemistry

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The correct order of the stoichiometries of $\mathrm{AgCl}$ formed when ${\mathrm{AgNO}}_{3}$ is treated in excess with the complexes: ${\mathrm{CoCl}}_{3}.6{\mathrm{NH}}_{3}, {\mathrm{CoCl}}_{3}.5{\mathrm{NH}}_{3}, {\mathrm{CoCl}}_{3}.4{\mathrm{NH}}_{3}$ , respectively, is:

Official previous-year question

Held on 30 Apr 2017 · Verified 9 Jul 2026.

Options

A
$1 \mathrm{AgCl}, 3 \mathrm{AgCl}, 2 \mathrm{AgCl}$
B
$3 \mathrm{AgCl}, 1 \mathrm{AgcCl}, 2 \mathrm{AgCl}$
C
$3 \mathrm{AgCl}, 2 \mathrm{AgCl}, 1 \mathrm{AgCl}$
D
$2 \mathrm{AgCl}, 3 \mathrm{AgCl}, 1 \mathrm{AgCl}$

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Solution

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]{\mathrm{Cl}}_{3}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}3 \mathrm{moles}$ of $\mathrm{AgCl}$

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{5}\mathrm{Cl}]{\mathrm{Cl}}_{2}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}2\mathrm{moles}$ of $\mathrm{AgCl}$

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Cl}}_{2}]\mathrm{Cl}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}1 \mathrm{mole}$ of $\mathrm{AgCl}$

The complexes are respectively $[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]{\mathrm{Cl}}_{3}, [\mathrm{Co}{({\mathrm{NH}}_{3})}_{5}\mathrm{Cl}]{\mathrm{Cl}}_{2}$ and $[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Cl}}_{2}]\mathrm{Cl}$ .

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Options

$1 \mathrm{AgCl}, 3 \mathrm{AgCl}, 2 \mathrm{AgCl}$

$3 \mathrm{AgCl}, 1 \mathrm{AgcCl}, 2 \mathrm{AgCl}$

$3 \mathrm{AgCl}, 2 \mathrm{AgCl}, 1 \mathrm{AgCl}$

$2 \mathrm{AgCl}, 3 \mathrm{AgCl}, 1 \mathrm{AgCl}$

Solution

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{6}]{\mathrm{Cl}}_{3}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}3 \mathrm{moles}$ of $\mathrm{AgCl}$

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{5}\mathrm{Cl}]{\mathrm{Cl}}_{2}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}2\mathrm{moles}$ of $\mathrm{AgCl}$

$[\mathrm{Co}{({\mathrm{NH}}_{3})}_{4}{\mathrm{Cl}}_{2}]\mathrm{Cl}\rightarrow _{}^{{\mathrm{AgNO}}_{3}}1 \mathrm{mole}$ of $\mathrm{AgCl}$

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