[Mn(CN)6]3−
Mn(III)=[Ar]3d4
CN− being strong field ligand forces pairing of electrons.
This gives t2g4eg0

∵The coordination number of Mn=6
∴ Structure=octahedral
[Mn(CN)6]3−=

NEET UG 2017 — Chemistry Inorganic Chemistry
Pick out the correct statement with respect to [Mn(CN)6]3−.
Held on 30 Apr 2017 · Verified 9 Jul 2026.
It is sp3d2 hybridised and octahedral.
It is sp3d2 hybridised and tetrahedral.
It is d2sp3 hybridised and octahedral.
It is dsp2 hybridised and square planar.
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