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It is because of the inability of ns^2 electrons of the valence shell to participate in bonding that

NEET UG 2017 — Chemistry Inorganic Chemistry

2017mcqeasy

It is because of the inability of ns2{\mathrm{ns}}^{2}ns2 electrons of the valence shell to participate in bonding that

Official previous-year question

Held on 30 Apr 2017 · Verified 9 Jul 2026.

Options

  1. A

    Sn2+{\mathrm{Sn}}^{2+}Sn2+ is reducing while Pb4+{\mathrm{Pb}}^{4+}Pb4+ is oxidizing.

  2. B

    Sn2+{\mathrm{Sn}}^{2+}Sn2+ is oxidizing while Pb4+{\mathrm{Pb}}^{4+}Pb4+ is reducing.

  3. C

    Sn2+{\mathrm{Sn}}^{2+}Sn2+ and Pb2+{\mathrm{Pb}}^{2+}Pb2+ are both oxidizing and reducing.

  4. D

    Sn4+{\mathrm{Sn}}^{4+}Sn4+ is reducing while Pb4+{\mathrm{Pb}}^{4+}Pb4+ is oxidizing.

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