In which of the following ionization processes the bond energy increases and the magnetic behaviour changes from paramagnetic to diamagnetic:

The molecular configuration is depicted below: Molecular orbital configuration of $$\begin{aligned} & \mathrm{O}_2 \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 \mathrm{~s}^2 \rightarrow \sigma 2 s^2 \rightarrow \sigma^* \\ & 2 s^2 \rightarrow \sigma 2 \mathrm{p}_z^2 \pi 2 p^2{ }_x \rightarrow \pi 2 p^2{ }_y \\ & \pi^* 2 \mathrm{p}_x^1 \rightarrow \pi^* 2 p^1{ }_y \\ & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{10-6}{2}=2 \\ & \mathrm{O}_2^{+} \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \rightarrow \sigma 2 s^2 \rightarrow \\ & \sigma^* 2 s^2 \rightarrow \sigma 2 p^2{ }_z \rightarrow \pi 2 \mathrm{p}_x^2 \\ & \pi 2 p^2{ }_y \rightarrow \pi^* 2 p^1{ }_x \\ & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{10-5}{2}=2.5 \\ & \mathrm{C}_2 \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \rightarrow \sigma 2 s^2 \rightarrow \\ & \sigma^* 2 s^2 \rightarrow \pi 2 p^2{ }_x \rightarrow \pi 2 p^2 \\ & \Rightarrow \text { Diamagnetic } \\ & \text { Bond order }=\frac{8-4}{2}=2 \\ & \mathrm{C}_2^{+} \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \rightarrow \sigma 2 s^2 \rightarrow \\ & \sigma^* 2 s^2 \rightarrow \pi 2 p^2{ }_x \rightarrow \pi 2 p^1{ }_y \end{aligned}$$​O2​⇒σ1s2→σ∗1 s2→σ2s2→σ∗2s2→σ2pz2​π2p2x​→π2p2y​π∗2px1​→π∗2p1y​⇒ Paramagnetic  Bond order =210−6​=2O2+​⇒σ1s2→σ∗1s2→σ2s2→σ∗2s2→σ2p2z​→π2px2​π2p2y​→π∗2p1x​⇒ Paramagnetic  Bond order =210−5​=2.5C2​⇒σ1s2→σ∗1s2→σ2s2→σ∗2s2→π2p2x​→π2p2⇒ Diamagnetic  Bond order =28−4​=2C2+​⇒σ1s2→σ∗1s2→σ2s2→σ∗2s2→π2p2x​→π2p1y​​ $$\begin{aligned} & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{7-4}{2}=15 \\ & \mathrm{NO} \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \rightarrow \sigma 2 s^2 \rightarrow \\ & \sigma^* 2 s^2 \rightarrow \sigma 2 p^2=\pi 2 p_x^2 \rightarrow \\ & \pi 2 p_y^2 \rightarrow \pi^* 2 p_x^1 \\ & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{10-5}{2}=2.5 \\ & \mathrm{NO}^{+} \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \sigma 2 s^2 \rightarrow \sigma^* 2 s^2 \\ & \sigma 2 p_z^2 \rightarrow \pi 2 p_x^2 \rightarrow \pi 2 p_y^2 \\ & \Rightarrow \text { Diamagnetic } \\ & \text { Bond } \text { order }=\frac{10-4}{2}=3 \\ & \mathrm{~N}_2 \Rightarrow \sigma 1 s^2 \rightarrow \sigma^* 1 s^2 \sigma 2 s^2 \rightarrow \sigma^* 2 s^2 \\ & \rightarrow \pi 2 p_x^2 \rightarrow \pi 2 p_y^2 \rightarrow \sigma 2 p^1= \\ & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{10-4}{2}=3 \\ & \mathrm{~N}_2^{+} \Rightarrow \sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p^2{ }_x \\ & \pi 2 p^2 \sigma 2 p_z^1 \\ & \Rightarrow \text { Paramagnetic } \\ & \text { Bond order }=\frac{9-4}{2}=2.5 \\ & \end{aligned}$$​⇒ Paramagnetic  Bond order =27−4​=15NO⇒σ1s2→σ∗1s2→σ2s2→σ∗2s2→σ2p2=π2px2​→π2py2​→π∗2px1​⇒ Paramagnetic  Bond order =210−5​=2.5NO+⇒σ1s2→σ∗1s2σ2s2→σ∗2s2σ2pz2​→π2px2​→π2py2​⇒ Diamagnetic  Bond  order =210−4​=3 N2​⇒σ1s2→σ∗1s2σ2s2→σ∗2s2→π2px2​→π2py2​→σ2p1=⇒ Paramagnetic  Bond order =210−4​=3 N2+​⇒σ1s2σ∗1s2σ2s2σ∗2s2π2p2x​π2p2σ2pz1​⇒ Paramagnetic  Bond order =29−4​=2.5​