NEET UG 2012 — Chemistry Inorganic Chemistry

2012mcqhard

Which one of the following does not correctly represent the correct order of the property indicated against it?

Official previous-year question

Held on 30 Apr 2012 · Verified 9 Jul 2026.

Options

A
$\mathrm{Ti} < \mathrm{V} < \mathrm{Cr} < \mathrm{Mn}$ : increasing number of oxidation states
B
$\mathrm{Ti}^{3+} < \mathrm{V}^{3+} < \mathrm{Cr}^{3+} < \mathrm{Mn}^{3+}$ : increasing magnetic moment
C
$\mathrm{Ti} < \mathrm{V} < \mathrm{Cr} < \mathrm{Mn}$ : increasing melting points
D
$\mathrm{Ti} < \mathrm{V} < \mathrm{Mn} < \mathrm{Cr}$ : increasing second ionisation enthalpy

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Solution

NEET 2012 Chemistry, d and f Block Elements — solution figure 1

$\therefore$ Order of oxidation states is $\mathrm{Ti} < \mathrm{V} < \mathrm{Cr} < \mathrm{Mn}$ (b) $\because$ Magnetic moment, $\mu=\sqrt{n(n+2)}$ where, $n=$ no. of unpaired electrons NEET 2012 Chemistry, d and f Block Elements — solution figure 2

$\therefore$ Order of magnetic moment is $\mathrm{Ti}^{3+} < \mathrm{V}^{3+} < \mathrm{Cr}^{3+} < \mathrm{Mn}^{3+}$ (c) In 3 -series melting point increases as we move from left to right. But Mn shows low melting point due to its complex formating nature. It is unable to form metallic and covalent bonds. (d) NEET 2012 Chemistry, d and f Block Elements — solution figure 3

$\therefore$ Order of second ionisation enthalpy is $\mathrm{Ti} < \mathrm{V} < \mathrm{Mn} < \mathrm{Cr}$

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NEET UG 2012 — Chemistry Inorganic Chemistry

2012mcqhard

Which one of the following does not correctly represent the correct order of the property indicated against it?

Official previous-year question

Held on 30 Apr 2012 · Verified 9 Jul 2026.

Options

A
$\mathrm{Ti} < \mathrm{V} < \mathrm{Cr} < \mathrm{Mn}$ : increasing number of oxidation states
B
$\mathrm{Ti}^{3+} < \mathrm{V}^{3+} < \mathrm{Cr}^{3+} < \mathrm{Mn}^{3+}$ : increasing magnetic moment
C
$\mathrm{Ti} < \mathrm{V} < \mathrm{Cr} < \mathrm{Mn}$ : increasing melting points
D
$\mathrm{Ti} < \mathrm{V} < \mathrm{Mn} < \mathrm{Cr}$ : increasing second ionisation enthalpy

Did you get this right?

Solution

NEET 2012 Chemistry, d and f Block Elements — solution figure 1

$\therefore$ Order of second ionisation enthalpy is $\mathrm{Ti} < \mathrm{V} < \mathrm{Mn} < \mathrm{Cr}$

NEET UG 2012 — Chemistry Inorganic Chemistry

Options

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Solution

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NEET UG 2012 — Chemistry Inorganic Chemistry

Options

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Solution

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NEET UG Inorganic Chemistry in other years

More NEET UG Inorganic Chemistry questions

Other Chemistry topics for NEET UG

Physical Chemistry

Organic Chemistry

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