The pairs of species of oxygen and their magnetic behaviours are noted below. Which of the following presents the correct description?

The molecular orbital configurations of $\mathrm{O}_2^{+}, \mathrm{O}_2^{-}, \mathrm{O}_2^{2-}$O2+​,O2−​,O22−​ and $\mathrm{O}_2$O2​ are $$\begin{aligned} & \mathrm{O}_2^{+}=\sigma 1 s^2, \sigma 1 s^2, \sigma 2 s^2, \sigma 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \approx \pi 2 p_y^2, \\ & \pi 2 p_x^1 \approx \pi 2 p_y^0 \\ & \mathrm{O}_2^{-}=\sigma 1 s^2, \sigma \cdot \% 1 s^2, \sigma 2 s^2, \sigma 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \\ & \approx \pi 2 p_y^2, \pi 2 p_x^2 \approx \pi 2 p_y^1 \\ & \mathrm{O}_2^{2-}=\sigma 1 s^2, \sigma \cdot s^2, \sigma 2 s^2, \sigma 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \\ & \approx \pi 2 p_y^2, \pi 2 p_x^2 \approx \pi 2 p_y^2 . \\ & \mathrm{O}_2=\sigma 1 s^2, \sigma 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \\ & \approx \pi 2 p_y^2, \pi 2 p_x^1 \approx \pi 2 p_y^1 \end{aligned}$$​O2+​=σ1s2,σ1s2,σ2s2,σ2s2,σ2pz2​,π2px2​≈π2py2​,π2px1​≈π2py0​O2−​=σ1s2,σ⋅%1s2,σ2s2,σ2s2,σ2pz2​,π2px2​≈π2py2​,π2px2​≈π2py1​O22−​=σ1s2,σ⋅s2,σ2s2,σ2s2,σ2pz2​,π2px2​≈π2py2​,π2px2​≈π2py2​.O2​=σ1s2,σ1s2,σ2s2,σ∗2s2,σ2pz2​,π2px2​≈π2py2​,π2px1​≈π2py1​​ And the electronic configuration of $\mathrm{O}$O and $\mathrm{O}^{+}$O+ are $$\begin{array}{r} \mathrm{O}=1 s^2, 2 s^2, 2 p_x^2, 2 p_y^1, 2 p_z^1 \\ \mathrm{O}^{+}=1 s^2, 2 s^2, 2 p_x^1, 2 p_y^1, 2 p_z^1 \end{array}$$O=1s2,2s2,2px2​,2py1​,2pz1​O+=1s2,2s2,2px1​,2py1​,2pz1​​ As $\mathrm{O}_2^{+}, \mathrm{O}_2, \mathrm{O}_2^{-}, \mathrm{O}$O2+​,O2​,O2−​,O and $\mathrm{O}^{+}$O+have unpaired electrons, hence are paramagnetic.