This can be understood on the basis of E∘ values for M2+/M. E%VM2+/MCr−0.90Mn−1.18Fe−0.44 Co −0.28 E∘ value for Mn is more negative than expected from general trend due to extra stability of half-filled Mn2+ ion. Thus the correct order should be, Mn>Cr>Fe>CO an examination of E∘ values for redox couple M3+/M2+ shows that Cr2+ is strong reducing agent(EM3+∘/M2+=0.41 V) and liberates H2 from dilute acids. 2Cr2+(aq)+2H+(aq)→2Cr3+(aq)+H2↑(g) ∴ The correct order is Mn>Fe>Cr>Co.
For the four successive transition elements (Cr, Mn, Fe and Co), the stability of +2 oxidation state will be there in which of the following order?…
NEET UG 2011 — Chemistry Inorganic Chemistry
For the four successive transition elements (Cr, Mn, Fe and Co), the stability of +2 oxidation state will be there in which of the following order? (At. no. Cr=24,Mn=25,Fe=26,Co=27 )
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
Fe >Mn>Co>Cr
- B
Co >Mn> Fe >Cr
- C
Cr > Mn > Co > Fe
- D
Mn > Fe > Cr > Co
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