Cr++(3 d4)=1111=4 unpaired e−Mn++(3 d4)=11111=5 unpaired e−Fe++(3 d6)= 1L 1111=4 unpaired e−Ni++(3 d8)= 1h 1L IL 11=2 unpaired e− As Ni++ has minimum no. of unpaired e− thus this is least paramagnetic.
The d electron configuration of Cr2+, Mn2+,Fe2+ and Ni2+ are 3 d4,3 d5,3 d6 and 3 d8 respectively. Which one of the following aqua complexes will exhibit the minimum paramagnetic behaviour? (At. No. Cr=24,Mn=25,Fe=26,Ni= 28)
Held on 30 Apr 2007 · Verified 9 Jul 2026.
[Fe(H2O)6]2+
[Ni(H2O)6]2+
[Cr(H2O)6]2+
[Mn(H2O)6]2+
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