[ Cr ( H_2 O )_6 ] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3 d electrons in the Chromium of the…
NEET UG 2006 — Chemistry Inorganic Chemistry
2006mcqhard
[Cr(H2O)6]Cl3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the Chromium of the complex is:
Official previous-year question
Held on 30 Apr 2006 · Verified 9 Jul 2026.
Options
A
(3dx2−y2)1,3dz21,3dxz
B
3dxy1,(3dx2−y2)1,3dyz1
C
3dxy1,3dyz1,3dxz1
D
3dxy1,3dyz1,3dz2′
Did you get this right?
Sign in to track your attempts and accuracy.
Solution
Magnetic moment (μ)3.833.83×3.8314.6689=n(n+2)BM=n(n+2)=n2+2n=n2+2n On solving this, we get n=3. Hence, the number of unpaired electrons in the d-subshell of the penultimate shell of chromium is 3 . So, Cr3+=1s2,2s22p6,3s23p23d3 In [Cr(H2O)6]Cl3, the oxidation state of Cr is +3 . Hence, in 3d3, the distribution of electrons is 3dxy1,3d1,3d1xx∗
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.