Magnetic moment (μ)3.833.83×3.8314.6689=n(n+2)BM=n(n+2)=n2+2n=n2+2n On solving this, we get n=3. Hence, the number of unpaired electrons in the d-subshell of the penultimate shell of chromium is 3 . So, Cr3+=1s2,2s22p6,3s23p23d3 In [Cr(H2O)6]Cl3, the oxidation state of Cr is +3 . Hence, in 3d3, the distribution of electrons is 3dxy1,3d1,3d1xx∗ 