Magnetic moment (μ)3.833.83×3.8314.6689=n(n+2)BM=n(n+2)=n2+2n=n2+2n On solving this, we get n=3. Hence, the number of unpaired electrons in the d-subshell of the penultimate shell of chromium is 3 . So, Cr3+=1s2,2s22p6,3s23p23d3 In [Cr(H2O)6]Cl3, the oxidation state of Cr is +3 . Hence, in 3d3, the distribution of electrons is 3dxy1,3d1,3d1xx∗ 
[ Cr ( H_2 O )_6 ] Cl_3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3 d electrons in the Chromium of the…
NEET UG 2006 — Chemistry Inorganic Chemistry
2006mcqhard
[Cr(H2O)6]Cl3 (at. no. or Cr=24 ) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the Chromium of the complex is:
Official previous-year question
Held on 30 Apr 2006 · Verified 9 Jul 2026.
Options
- A
(3 dx2−y2)1,3 dz21,3dxz
- B
3 dxy1,(3 dx2−y2)1,3 dyz1
- C
3 dxy1,3 dyz1,3 dxz1
- D
3 dxy1,3dyz1,3dz2′
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