Oxidation state of sulphur is SO32− i 4 Oxidation state of sulphur in S2O42− is 3 Oxidation state of sulphur in S2O62− is 5 The correct order of oxidation state is as follows: S2O42−<SO32−<S2O62−
NEET UG 2003 — Chemistry Inorganic Chemistry
The oxidation states of sulphur in the anions SO32, S2O42− and S2O62− follow of order
Held on 30 Apr 2003 · Verified 9 Jul 2026.
S2O42−<SO32−<S2O62−
SO32−<S2O32−<S2O62−
S2O42−<S2O62−<SO32−
S2O62−<S2O42−<SO32−
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