Thermodynamics PYQ — Page 16
JEE Main Physics — Thermodynamics previous year questions with solutions.
All Thermodynamics Questions (487)
The temperature, at which the root mean square velocity of hydrogen molecules equals their escape their escape velocity from the earth, is closest to: $[$ Boltzmann Constant ${k}_{B}=1.38\times {10}^{-23} J/K$ Avogadro number ${N}_{A}=6.02\times {10}^{26} /kg$ Radius of Earth: $6.4\times {10}^{6} m$ Gravitational acceleration on Earth $=10 m{s}^{-2}]$
A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Considering only translational and rotational modes, the total internal energy of the system is
Two rods $A$ and $B$ of identical dimensions are at temperature $30^{\circ} \mathrm{C}$. If $\mathrm{A}$ is heated upto $180^{\circ} \mathrm{C}$ and $\mathrm{B}$ upto $\mathrm{T}^{\circ} \mathrm{C},$ then the new lengths are the same. If the ratio of the coefficients of linear expansion of $\mathrm{A}$ and $\mathrm{B}$ is $4: 3,$ then the value of $T$ is
In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation $\mathrm{VT}=\mathrm{K},$ where $\mathrm{K}$ is a constant. In this process the temperature of the gas is increased by $\Delta \mathrm{T}$. The amount of heat absorbed by gas is (R is gas constant):
$2\mathrm{kg}$ of a monoatomic gas is at a pressure of $4\times {10}^{4}N{m}^{-2}$. The density of the gas is $8 \mathrm{kg}{m}^{-3}$. What is the order of energy of the gas due to its thermal motion?
When $100 \mathrm{~g}$ of a liquid $\mathrm{A}$ at $100^{\circ} \mathrm{C}$ is added to $50 \mathrm{~g}$ of a liquid $B$ at temperature $75^{\circ} \mathrm{C}$, the temperature of the mixture becomes $90^{\circ} \mathrm{C}$. The temperature of the mixture, if $100 \mathrm{~g}$ of liquid $A$ at $100^{\circ} \mathrm{C}$ is added to $50 \mathrm{~g}$ of liquid $\mathrm{B}$ at $50^{\circ} \mathrm{C}$, will be:
A thermally insulated vessel contains $150 g$ of water at $0^{\circ}C$ . Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at $0^{\circ}C$ itself. The mass of evaporated water will be closest to: (Latent heat of vaporization of water $=2.10\times {10}^{6} J k{g}^{-1}$ and Latent heat of Fusion of water $=3.36\times {10}^{5} J k{g}^{-1}$ )
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume for this process is $\mathrm{TV}^{\mathrm{x}}=$ constant, then $\mathrm{x}$ is:
An unknown metal of mass $192 g$ heated to a temperature of $100^{\circ}C$ was immersed into a brass calorimeter of mass $128 g$ containing $240 g$ of water at a temperature of ${8.4}^{o}C.$ Calculate the specific heat of the unknown metal if water temperature stabilizes at ${21.5}^{o}C.$ $($ Specific heat of brass is $394J k{g}^{-1}{K}^{-1})$
One mole of an ideal gas passes through a process where pressure and volume obey the relation $P={P}_{o}[1-\frac{1}{2}{(\frac{{V}_{o}}{V})}^{2}]$ . Here ${P}_{o}$ and ${V}_{o}$ are constants. Calculate the change in the temperature of the gas if its volume changes from ${V}_{o}$ to $2{V}_{o}$ .
An ideal gas occupies a volume of $2{m}^{3}$ at a pressure of $3\times {10}^{6}Pa.$ The energy of the gas is:
$1\mathrm{kg}$ of water, at $20 ^{\circ}C$ is heated in an electric kettle whose heating element has a mean (temperature averaged) resistance of $20 \Omega .$ The rms voltage in the mains is $200 V$. Ignoring heat loss from the kettle, time taken for water to evaporate fully is close to [ Specific heat of water $=4200 J{\mathrm{kg}}^{-1}^{\circ}{C}^{-1}$ Latent heat of water $=2260 kJk{g}^{-1}$ ]
$n$ moles of an ideal gas with constant volume heat capacity ${C}_{v}$ undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is:
A $25\times {10}^{-3} {m}^{3}$ volume cylinder is filled with $1$ mol of ${O}_{2}$ gas at room temperature $(300 K)$ . The molecular diameter of ${O}_{2}$ , and its root mean square speed, are found to be $0.3 nm$ and $200 m/s$ , respectively. What is the average collision rate (per second) for an ${O}_{2}$ molecule?
A heat source at $T={10}^{3}K$ is connected to another heat reservoir at $T={10}^{2}K$ by a copper slab which is $1 m$ thick. Given that the thermal conductivity of copper is $0.1 W{K}^{-1} {m}^{-1}$, the energy flux through it in the steady-state is:
At $40^{\circ}C,$ a brass wire of $1 mm$ radius is hung from the ceiling. A small mass, $M$ is hung from the free end of the wire. When the wire is cooled down from $40^{\circ}C$ to $20^{\circ}C$ it regains its original length of $0.2 m.$ The value of $M$ is close to: (Coefficient of linear expansion and Young’s modulus of brass are ${10}^{-5}{/}^{^{\circ}}C$ and ${10}^{11} N/{m}^{2},$ respectively; $g=10 m {s}^{-2}$ )
A uniform cylindrical rod of length $L$ and radius r, is made from a material whose Young’s modulus of Elasticity equals $Y.$ When this rod is heated by temperature T and simultaneously subjected to a net longutudinal compressional force F, its length remains unchanged. The coefficient of volume expansion, of the material of the rod, is (nearly) equal to:
The number density of molecules of a gas depends on their distance r from the origin as, $n(r)={n}_{0}{e}^{-\alpha {r}^{4}}.$ Then the numer of molecules is proportional to:
Temperature difference of ${120}^{o}C$ is maintained between two ends of a uniform rod $AB$ of length $2L.$ Another bent rod $PQ,$ of same cross-section as $AB$ and length $\frac{3L}{2},$ is connected across $AB$ (See figure). In steady state, temperature difference between $P$ and $Q$ will be close to: 
One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, $27^{\circ} \mathrm{C}$. The work done on the gas will be:
The value closest to the thermal velocity of a Helium atom at room temperature $(300 \mathrm{~K})$ in $\mathrm{ms}^{-1}$ is: $\left[\mathrm{k}_{\mathrm{B}}=1.4 \times 10^{-23} \mathrm{~J} / \mathrm{K} ; \mathrm{m}_{\mathrm{He}}=7 \times 10^{-27} \mathrm{~kg}\right]$
One mole of an ideal monatomic gas is taken along the path $ABCA$ as shown in the $PV$ diagram. The maximum temperature attained by the gas along the path $BC$ is given by: 
One mole of an ideal monatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, ${27}^{o}C$ . The magnitude of work done on the gas will be:
Two moles of helium are mixed with n moles of hydrogen. If $\frac{{C}_{p}}{{C}_{v}}=\frac{3}{2}$ for the mixture then the value of $n$ is,