Organic Chemistry PYQ — Page 6

Given below are two statements : Statement I: The two cyclic forms of D-(+)-glucose (α and β anomers differing at C1 hydroxyl orientation) are two anomers of D-(+)-glucose. Statement II: The open chain forms of D-glucose and D-fructose contain three similar chiral carbons at $C_3$, $C_4$ and $C_5$. In the light of the above statements, choose the correct answer from the options given below :

Match List - I with List - II. $\begin{array}{l} \text{List - I} & \text{List - II} \\ \text{Pair of Compounds} & \text{Type of Isomers} \\ \text{A. 2-Methylpropene and but-1-ene} & \text{I. Stereoisomers} \\ \text{B. Cis-but-2-ene and trans-but-2-ene} & \text{II. Position isomers} \\ \text{C. 2-Butanol and diethyl ether} & \text{III. Chain isomers} \\ \text{D. But-1-ene and but-2-ene} & \text{IV. Functional group isomers} \end{array}$ Choose the correct answer from the options given below :

Match List - I with List - II. <table class="pyq-table"><tbody><tr><th>List - I Mixture of Compounds</th><th>List - II Reagent used to distinguish</th></tr><tr><td>A. Diethyl amine + Ethyl amine</td><td>I. Bromine water</td></tr><tr><td>B. Acetaldehyde + Acetone</td><td>II. $CHCl_3 + KOH, \Delta$</td></tr><tr><td>C. Ethanol + Phenol</td><td>III. Neutral $FeCl_3$</td></tr><tr><td>D. Benzoic acid + Cinnamic acid</td><td>IV. Ammonical silver nitrate</td></tr></tbody></table> Choose the correct answer from the options given below :

$\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}_{2} \xrightarrow[\mathrm{HBr}]{(\mathrm{PhCOO})_{2}}$ Product Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B. The role of peroxide is to generate $\mathrm{H}^{\circ}$ (Hydrogen radical). C. During this reaction, benzene is formed as a byproduct. D. 1-Bromo-2-phenylethane is formed as the minor product. E. The same reaction in absence of peroxide proceeds via carbocation intermediate. Identify the correct statements. Choose the correct answer from the options given below:

Correct statements regarding alkyl halides $(R - X)$ among the following are: A. Alcohol being less polar solvent as compared to water, alcoholic KOH favours elimination reaction with $R - X$. B. Order of reactivity towards $S_N^1$ mechanism is $C_6 H_5 - CH_2 - Cl > C_6 H_5 - CHCl - C_6 H_5$. C. Non substituted aryl halides exhibit properties similar to alkyl halides. D. Vinyl chloride is an example of haloalkene and allyl chloride is an example of haloalkyne. E. $R - Cl$ can be prepared by reacting $R - OH$ with $SOCl_2$ but $Ar - Cl$ cannot be prepared by reacting $Ar - OH$ with $SOCl_2$. Choose the correct answer from the options given below:

Match the LIST-I with LIST-II <table class="pyq-table"><tbody><tr><th>List-I (Chloro derivative)</th><th>List-II (Example)</th></tr><tr><td>A. Vinyl Chloride</td><td>I. $CH_2 = CH - CH_2Cl$</td></tr><tr><td>B. Benzyl chloride</td><td>II. $CH_3 = CH(Cl)CH_3$</td></tr><tr><td>C. Alkyl chloride</td><td>III. $CH_2 = CHCl$</td></tr><tr><td>D. Allyl chloride</td><td>IV. <img src="https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Haloalkanes_and_Haloarenes/6983c1a28bfdbb243563972d/question_1__q_6983c1a28bfdbb243563972d__cdn-question-pool.getmarks.app__24S1_q_60_1_v2__1278b37ed2_final_ppt_sync.png" alt="JEE Main 2026 Chemistry, Haloalkanes and Haloarenes — question figure"></td></tr></tbody></table> Choose the correct answer from the options given below:

Given below are two statements: Statement I: ' $\mathrm{C}-\mathrm{Cl}^{\prime}$ bond is stronger in $\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{Cl}$ than $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{Cl}$ Statement II: The given optically active molecule,  on hydrolysis gives a solution that can rotate the plane polarized light. In the light of the above statements, choose the correct answer from the options given below

The correct order of reactivity of $\mathrm{CH}_{3} \mathrm{Br}$ in methanol with the following nucleophiles is $\mathrm{F}^{-}, \mathrm{I}^{-}, \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}$and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}$

The correct order of the rate of the reaction for the following reaction with respect to nucleophiles is : $\mathrm{CH}_{3} \mathrm{Br}+\mathrm{Nu}^{\ominus} \longrightarrow \mathrm{CH}_{3} \mathrm{Nu}+\mathrm{Br}^{\ominus}$

Benzyl isocyanide can be obtained from  Choose the correct answer from the options given below:

Match the LIST-I with LIST-II <table class="pyq-table"><tbody><tr><th>List-I (Compound)</th><th>List-II (Test)</th></tr><tr><td>A. Cyclohexanol</td><td>I. Hinsberg's reagent test</td></tr><tr><td>B. Cyclohexylamine</td><td>II. Phthalein dye test</td></tr><tr><td>C. Cyclohexanecarbaldehyde</td><td>III. Lucas test</td></tr><tr><td>D. Phenol</td><td>IV. Tollen's test</td></tr></tbody></table> Choose the correct answer from the options given below:

Amongst the following, the total number of compounds soluble in aqueous $NaOH$ at room temperature is: 

From the following, how many compounds contain at least one secondary alcohol?  Choose the correct answer from the options given below:

Consider the following two reactions A and B.  Numerical value of [molar mass of $x+$ molar mass of $y$] is $\_\_\_\_$.

3, 3-Dimethyl-2-butanol cannot be prepared by :  Choose the correct answer from the options given below :

'$x$' is the product which is obtained from benzene by reacting it with carbon monoxide and hydrogen chloride in the presence of cuprous chloride. '$y$' is the major product obtained from the benzene by reacting it with ethanoyl chloride in the presence of anhydrous AlCl$_3$. Product (major) obtained by heating $x$ and $y$ in the presence of alkali is $z$. Total number of $\pi$ (pi) electrons in $z$ is ________.

Consider the following reaction.  The major product (P) formed is:

Given below are the four isomeric compounds $(\mathrm{P}, \mathrm{Q}, \mathrm{R}, \mathrm{S})$  Identify correct statements from below. A. $\mathrm{Q}, \mathrm{R}$ and S will give precipitate with $2,4-\mathrm{DNP}$. B. P and Q will give positive Bayer's test. C. Q and R will give sooty flame. D. R and S will give yellow precipitate with $\mathrm{I}_{2} / \mathrm{NaOH}$. E. Q alone will deposit silver with Tollen's reagent Choose the correct option.

The compound A, $\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}_{2}$ reacts with acetophenone to form a single product via cross-Aldol condensation. The compound A on reaction with conc. NaOH forms a substituted benzyl alcohol as one of the two products. The compound A is :

The correct order of acidic strength of the major products formed in the given reactions, is : A.  B. $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO} \xrightarrow[\Delta]{\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}, \mathrm{OH}^{-}}[\mathrm{B}]$ C. $\mathrm{CH}_{4}+\mathrm{O}_{2} \xrightarrow[\text { (ii) } \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} / \mathrm{H}^{+}]{\text {(i) }}[\mathrm{C}]$ D. $\mathrm{PhCH}_{2} \mathrm{MgBr}+\mathrm{CO}_{2} \xrightarrow[\mathrm{H}_{3} \mathrm{O}^{+}]{\text {Dry ether }}[\mathrm{D}]$ Choose the correct answer from the options given below :

Given below are two statements : Statement I: Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine. Statement II: Nitration of aniline with $HNO_3/H_2SO_4$ at $288\text{ K}$ produces $m$-nitroaniline in higher amount than $o$-nitroaniline (pH adjusted). In the light of the above statements, choose the correct answer from the options given below :

A student performed analysis of aliphatic organic compound ' $X$ ' which on analysis gave $C=61.01 \%$, $\mathrm{H}=15.25 \%, \mathrm{~N}=23.74 \%$. This compound, on treatment with $\mathrm{HNO}_{2} / \mathrm{H}_{2} \mathrm{O}$ produced another compound ' Y ' which did not contain any nitrogen atom. However, the compound ' $Y$ ' upon controlled oxidation produced another compound ' $Z$ ' that responded to iodoform test. The structure of ' $X$ ' is :

The correct stability order of the following diazonium salts is 

A hydrocarbon ' $\mathrm{P}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{8}\right)$ on reaction with HCl gives an optically active compound ' Q ' $\left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{Cl}\right)$ which on reaction with one mole of ammonia gives compound ' $\mathrm{R}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{11} \mathrm{~N}\right)$. ' $\mathrm{R}^{\prime}$ on diazotization followed by hydrolysis gives ' S '. Identify $\mathrm{P}, \mathrm{Q}, \mathrm{R}$ and S.