CUET UG Mathematics — Geometry previous year questions with solutions.
The two lines given by $\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \mu(\hat{i} - \hat{j} + \hat{k})$ and $\vec{r} = (2\hat{i} - \hat{j} - \hat{k}) + \mu(-\hat{i} + \hat{j} - \hat{k})$ A. are perpendicular B. are parallel. C. have shortest distance 0. D. have shortest distance $\sqrt{26}$. E. have shortest distance $\sqrt{78}$. Which of the above statements are true? Choose the correct answer from the options given below:
The correct order of steps from A to E, for finding value of p, so that the lines $\frac{1-x}{3} = \frac{7y-14}{2p} = \frac{z-3}{2}$ and $\frac{7-7x}{3p} = \frac{y-5}{1} = \frac{6-z}{5}$ are at right angle is: A. $p = \frac{70}{11}$ B. $(-3) \times \left(\frac{-3p}{7}\right) + 1 \times \left(\frac{2p}{7}\right) + 2 \times (-5) = 0$ C. $\frac{x-1}{-3} = \frac{y-2}{2\frac{p}{7}} = \frac{z-3}{2}$, $\frac{x-1}{-\frac{3p}{7}} = \frac{y-5}{1} = \frac{z-6}{-5}$ D. $\frac{9p}{7} + \frac{2p}{7} - 10 = 0$ E. $\frac{11p}{7} = 10$ Choose the correct answer from the options given below:
Image of origin with respect to plane $x + y + z = 3$ is:
If the vertices of a triangle ABC are $A(1, 2, 1)$, $B(4, 2, 3)$ and $C(2, 3, 1)$, then the equation of the median passing through the vertex $A$, is
A line makes the angle $\theta$ with each of the $x$ and $z$ axes. If the angle $\beta$ which it makes with $y$-axis is such that $\sin^2\beta = 3\sin^2\theta$, then the value of $\cos^2\theta$ is
$\sin^{-1}(1 - x) - 2\sin^{-1}x = \frac{\pi}{2}$, than $x$ is equal to (a) $0$ (b) $1$ (c) $\frac{1}{2}$ (d) $2$ Choose the most appropriate answer from the options given below:
The value of $\sin\left[2\cot^{-1}\left(\frac{-5}{12}\right)\right]$ is :
The shortest distances of the point $(1, 2, 3)$ from $x$, $y$, $z$ axes respectively are
Distance between two planes $x + 2y - z = 5$ and $2x + 4y - 2z + 2 = 0$ is
The value of $\alpha$ is
$\tan(\alpha + \beta) =$
Area of $\triangle ABD$ is
$\angle ABC$ is equal to:
The value of $\frac{1}{AB^2} + \frac{1}{BC^2}$ is:
Match List - I with List - II | List - I | List - II | |---|---| | A. $\tan^{-1}\left(\tan\frac{7\pi}{6}\right)$ | I. $\frac{5\pi}{6}$ | | B. $\tan^{-1}\left(\tan\frac{8\pi}{6}\right)$ | II. $\frac{\pi}{2}$ | | C. $\tan^{-1}\frac{1}{\sqrt{3}} + cosec^{-1}\frac{2}{\sqrt{3}}$ | III. $\frac{\pi}{6}$ | | D. $\cos^{-1}\left(\cos\frac{5\pi}{6}\right)$ | IV. $\frac{\pi}{3}$ | Choose the correct answer from the options given below:
The value of $\sec^2(\tan^{-1}2) + cosec^2(\cot^{-1}3)$ is:
The points of trisection of the segment joining the points (1, 0, 2) and (1, 3, 2) are: A. $(1, \frac{3}{2}, \frac{4}{3})$ B. (1, 1, 2) C. (1, 2, 2) D. $(1, \frac{3}{2}, 2)$ Choose the correct answer from the options given below:
The equation of line of intersection of the planes $x + y + 3z = 7$ and $x - y + 2z = 3$ is:
The distance of the point (1, 2, 0) from the line $\frac{x-3}{2} = \frac{y+4}{3} = \frac{z+6}{5}$ measured parallel to the plane $x + y + z = 3$ is
The line $\frac{x+2}{3} = \frac{y+3}{5} = \frac{z-6}{4}$ passes through (a, 2, c). The value of a and c are:
The Principal value of $\cos^{-1} \left( -\frac{1}{2} \right)$ is:
If two lines $\frac{x-3}{2} = \frac{y-4}{5} = \frac{z}{4}$ and $\frac{x-4}{3} = \frac{y-5}{6} = \frac{1-z}{k}$, are coplanar, then $k$ is equal to
The foot of perpendicular from the point P (1, 2, -3) to the line $\frac{x+1}{2} = \frac{y-3}{-2} = \frac{z}{-1}$ is
The equation of plane passing through the point of (3, 2, 0) and containing the line $\frac{x-2}{2} = \frac{y+3}{4} = \frac{z-1}{1}$ is