Domain requires x∈[0,1].
Maximum of sin−1(1−x) on [0,1] is 2π (at x=0), and sin−1x is non-negative on [0,1].
For LHS to equal 2π, we need sin−1(1−x)=2π and sin−1x=0 simultaneously. Both occur only at x=0.
So only (a) is valid.
sin^-1(1 - x) - 2sin^-1x = π 2, than x is equal to (a) 0 (b) 1 (c) 1 2 (d) 2 Choose the most appropriate answer from the options given below:
CUET UG 2022 — Mathematics Geometry
2022mcqmedium
sin−1(1−x)−2sin−1x=2π, than x is equal to
(a) 0
(b) 1
(c) 21
(d) 2
Choose the most appropriate answer from the options given below:
Official previous-year question
Held on 30 Aug 2022 · Verified 13 Jul 2026.
Options
- A
(a) and (b) only
- B
(a) and (c) only
- C
(a) only
- D
(c) only
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