Direction of line =n1×n2 where n1=(1,1,3) and n2=(1,−1,2).
n1×n2=(1⋅2−3⋅(−1), 3⋅1−1⋅2, 1⋅(−1)−1⋅1)=(5,1,−2).
For a point: set z=0: x+y=7, x−y=3⇒x=5,y=2.
Line: 5x−5=1y−2=−2z.
CUET UG 2022 — Mathematics Geometry
The equation of line of intersection of the planes x+y+3z=7 and x−y+2z=3 is:
Held on 4 Aug 2022 · Verified 13 Jul 2026.
1x−2=1y−2=3z−1
1x−1=−1y−1=2z−3
−1x=1y−1=−2z−2
5x−5=1y−2=−2z
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
Consider $f(x) = \sin(3x) + 4, \forall x \in \mathbb{R}$. Then (A) Maximum value of $f(x)$ is 5 (B) Minimum value of $f(x)$ is 3 (C) Maximum value of $f(x)$ is attained at $x = \frac{\pi}{6}$ (D) Minimum value of $f(x)$ is attained at $x = 0$ Choose the correct answer from the options given below:
The maximum value of $\sin x \cdot \cos x$ is:
The angle between the pair of lines given by $\vec{r} = \hat{i} + 2\hat{j} - 3\hat{k} + \lambda (\hat{i} - 2\hat{j} + 2\hat{k})$ and $\vec{r} = 5\hat{i} + \hat{j} + \hat{k} + \mu (3\hat{i} - 2\hat{j} + 6\hat{k})$ is
The minimum value of the function $f(x) = 3\sin x - 4\cos x, x \in [-4\pi, 4\pi]$ is equal to
Acute angle between the lines $\frac{x}{3} = \frac{y}{4} = \frac{z}{5}$ and $\frac{x-1}{4} = \frac{y+1}{-3} = \frac{z+10}{5}$ is:
Work through every CUET UG Geometry PYQ, year by year.