General point on line: Q=(2t−1,−2t+3,−t).
PQ=(2t−2,−2t+1,−t+3).
PQ perpendicular to direction (2,−2,−1):
2(2t−2)−2(−2t+1)−1(−t+3)=9t−9=0, so t=1.
Q=(1,1,−1).
The foot of perpendicular from the point P (1, 2, -3) to the line 2x+1=−2y−3=−1z is
Held on 6 Aug 2022 · Verified 13 Jul 2026.
(1,1,1)
(1,−1,1)
(1,1,−1)
(−1,1,1)
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