Direction-cosine identity: cos2α+cos2β+cos2γ=1 with α=γ=θ.
So 2cos2θ+cos2β=1, i.e., sin2β=2cos2θ.
Given sin2β=3sin2θ=3(1−cos2θ).
Equate: 2cos2θ=3−3cos2θ, so cos2θ=53.
Note: Options (1) and (4) appear identical in the paper; we have selected option (3) which matches the computed value.