Line passes through (2,−3,1) with direction (2,4,1).
Vector from (3,2,0) to (2,−3,1): (−1,−5,1).
Normal =(−1,−5,1)×(2,4,1)=(−9,3,6), or (3,−1,−2).
Plane: 3(x−3)−(y−2)−2z=0, i.e. 3x−y−2z=7.
The equation of plane passing through the point of (3, 2, 0) and containing the line x-2 2 = y+3 4 = z-1 1 is
CUET UG 2022 — Mathematics Geometry
2022mcqmedium
The equation of plane passing through the point of (3, 2, 0) and containing the line 2x−2=4y+3=1z−1 is
Official previous-year question
Held on 6 Aug 2022 · Verified 13 Jul 2026.
Options
- A
3x−y−2z=7
- B
3x−y+2z=7
- C
x+y−2z=5
- D
x−y+2z=1
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