Let θ1=tan−12, so tanθ1=2. Then sec2θ1=1+tan2θ1=1+4=5.
Let θ2=cot−13, so cotθ2=3. Then cosec2θ2=1+cot2θ2=1+9=10.
Sum =5+10=15.
The value of sec2(tan−12)+cosec2(cot−13) is:
Held on 4 Aug 2022 · Verified 13 Jul 2026.
9
5
10
15
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