Match List - I with List - II | List - I | List - II | |---|---| | A. $\tan^{-1}\left(\tan\frac{7\pi}{6}\right)$ | I. $\frac{5\pi}{6}$ | | B. $\tan^{-1}\left(\tan\frac{8\pi}{6}\right)$ | II. $\frac{\pi}{2}$ | | C. $\tan^{-1}\frac{1}{\sqrt{3}} + cosec^{-1}\frac{2}{\sqrt{3}}$ | III. $\frac{\pi}{6}$ | | D. $\cos^{-1}\left(\cos\frac{5\pi}{6}\right)$ | IV. $\frac{\pi}{3}$ | Choose the correct answer from the options given below:

Match List - I with List - II | List - I |… - CUET UG 2022 Mathematics PYQ

CUET UG 2022 — Mathematics Geometry

2022mcqmedium

Match List - I with List - II

List - I	List - II
A. $\tan^{-1}\left(\tan\frac{7\pi}{6}\right)$	I. $\frac{5\pi}{6}$
B. $\tan^{-1}\left(\tan\frac{8\pi}{6}\right)$	II. $\frac{\pi}{2}$
C. $\tan^{-1}\frac{1}{\sqrt{3}} + cosec^{-1}\frac{2}{\sqrt{3}}$	III. $\frac{\pi}{6}$
D. $\cos^{-1}\left(\cos\frac{5\pi}{6}\right)$	IV. $\frac{\pi}{3}$

Choose the correct answer from the options given below:

Official previous-year question

Held on 4 Aug 2022 · Verified 13 Jul 2026.

A: $\tan(7\pi/6) = \tan(\pi/6) = 1/\sqrt{3}$ , so $\tan^{-1}(1/\sqrt{3}) = \pi/6$ - III.

B: $\tan(8\pi/6) = \tan(4\pi/3) = \tan(\pi/3) = \sqrt{3}$ , so result $= \pi/3$ - IV.

C: $\pi/6 + \pi/3 = \pi/2$ - II.

D: $5\pi/6 \in [0,\pi]$ , so result $= 5\pi/6$ - I.

So A-III, B-IV, C-II, D-I.

Work through every CUET UG Geometry PYQ, year by year.