A: tan(7π/6)=tan(π/6)=1/3, so tan−1(1/3)=π/6 - III.
B: tan(8π/6)=tan(4π/3)=tan(π/3)=3, so result =π/3 - IV.
C: π/6+π/3=π/2 - II.
D: 5π/6∈[0,π], so result =5π/6 - I.
So A-III, B-IV, C-II, D-I.
Match List - I with List - II
| List - I | List - II |
|---|---|
| A. tan−1(tan67π) | I. 65π |
| B. tan−1(tan68π) | II. 2π |
| C. tan−131+cosec−132 | III. 6π |
| D. cos−1(cos65π) | IV. 3π |
Choose the correct answer from the options given below:
Held on 4 Aug 2022 · Verified 13 Jul 2026.
A-III, B-II, C-IV, D-I
A-I, B-II, C-IV, D-III
A-III, B-IV, C-II, D-I
A-I, B-II, C-III, D-IV
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