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A mass falls from a height ' h ' and its time of fall ' t ' is recorded in terms of time period T of a simple pendulum. On the surface of earth it is…

NEET UG 2019 — Physics Waves & Oscillations

2019mcqmedium

A mass falls from a height ' hhh ' and its time of fall ' ttt ' is recorded in terms of time period TTT of a simple pendulum. On the surface of earth it is found that t=2 Tt=2 \mathrm{~T}t=2 T. The entire set uuu is taken on the surface of another planet whose mass is half of earth and radius the same. Same experiment is repeated and corresponding times noted as t′\mathrm{t}^{\prime}t′ and T′\mathrm{T}^{\prime}T′.

Official previous-year question

Held on 30 Apr 2019 · Verified 9 Jul 2026.

Options

  1. A

    t′=2T′t^{\prime}=\sqrt{2} T^{\prime}t′=2​T′

  2. B

    t′>2T′t^{\prime}>2 T^{\prime}t′>2T′

  3. C

    t′<2T′t^{\prime} < 2 T^{\prime}t′<2T′

  4. D

    t′=2T′t^{\prime}=2 T^{\prime}t′=2T′

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