Skip to main content

A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be:

NEET UG 2015 — Physics Waves & Oscillations

2015mcqmedium

A particle is executing a simple harmonic motion. Its maximum acceleration is α\alphaα and maximum velocity is β\betaβ. Then, its time period of vibration will be:

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

  1. A

    αβ\frac{\alpha }{\beta }βα​

  2. B

    β2α\frac{{\beta }^{2}}{\alpha }αβ2​

  3. C

    2πβα\frac{2\pi \beta }{\alpha }α2πβ​

  4. D

    β2α2\frac{{\beta }^{2}}{{\alpha }^{2}}α2β2​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

NEET UG Waves & Oscillations in other years

More NEET UG Waves & Oscillations questions

Other Physics topics for NEET UG

Keep practicing Waves & Oscillations

Work through every NEET UG Waves & Oscillations PYQ, year by year.

Browse all Physics topics