According to question Length of wire =L=100 cm And ratio of fundamental frequencies =1:3:5 
L1:L2:L3=11:31:51=15:5:3 Let x= comman factor then 15x+5x+3x=100⇒2x=100⇒x=23100∴L1=15×23100=231500 cm∴L2=5×23100=231500 cm ∴L3=3×23100=23300 cm This shows that bridge should be placed from A at 231500 cm and 232000 cm respectively