When a string is divided into three segments of lengths l_1, l_2 and l_3, the fundamental frequencies of these three segments are v_1, v_2 and v_3…
NEET UG 2012 — Physics Waves & Oscillations
2012mcqmedium
When a string is divided into three segments of lengths l1,l2 and l3, the fundamental frequencies of these three segments are v1, v2 and v3 respectively. The original fundamental frequency (v) of the string is
Official previous-year question
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Options
A
v=v1+v2+v3
B
v=v1+v2+v3
C
v1=v11+v21+v31
D
v1=v11+v21+v31
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Solution
The fundamental frequency of string v∴v1l1=2l1mT=v2l2=v2l3=k From Eq. (i) l1=v1k,l2=v2k,l3=v3k Original length llvkv1=vk=l1+l2+l3=v1k+v2k+v3k=v11+v21+v31 Here, l=l1+l2+l3vk=v1k+v2k+v3kv1=v11+v21+v31
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