Δv=2ℓ1V−2ℓ2V=2V[ℓ11−ℓ21] =21μT{ℓ11−ℓ21}
Each of the two strings of length 51.6 ~cm and 49.1 ~cm are tensioned separately by 20 ~N force. Mass per unit length of both the strings is same and…
NEET UG 2009 — Physics Waves & Oscillations
Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
Options
- A
3
- B
5
- C
7
- D
8
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