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Each of the two strings of length 51.6 ~cm and 49.1 ~cm are tensioned separately by 20 ~N force. Mass per unit length of both the strings is same and…

NEET UG 2009 — Physics Waves & Oscillations

2009mcqmedium

Each of the two strings of length 51.6 cm51.6 \mathrm{~cm}51.6 cm and 49.1 cm49.1 \mathrm{~cm}49.1 cm are tensioned separately by 20 N20 \mathrm{~N}20 N force. Mass per unit length of both the strings is same and equal to 1 g/m1 \mathrm{~g} / \mathrm{m}1 g/m. When both the strings vibrate simultaneously the number of beats is :

Official previous-year question

Held on 30 Apr 2009 · Verified 9 Jul 2026.

Options

  1. A

    3

  2. B

    5

  3. C

    7

  4. D

    8

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