v=ωA2−x2 =T2πa2−4a2= Tπa3
A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at x= a / 2 will be :
NEET UG 2009 — Physics Waves & Oscillations
A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at x=a/2 will be :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
Options
- A
Tπa3
- B
2 Tπa3
- C
Tπa
- D
T3π2a
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