v=dtdy=Aωcosωt=Aω1−sin2ωt=ωA2−y2 Here, y=2a ∴v=ωa2−4a2=ω43a2=T2π2a3= Tπa3
NEET UG 2009 — Physics Waves & Oscillations
A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at x=2a will be
Held on 30 Apr 2009 · Verified 9 Jul 2026.
2 Tπa3
Tπa
T3π2a
Tπa3
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