Key Idea : Phase difference =λ2π× path difference Path difference between two points, Δx=15−10=5 m Time period, T=0.05 s ⇒ frequency v=T1=0.051=20 Hz Velocity, y=300 m/s ∴ Wavelength, λ=vv=20300=15 m Hence, phase difference Δϕ=λ2π×Δx=152π×5=32π
Two points are located at a distance of 10 ~m and 15 ~m from the source of oscillation. The period of oscillation is 0.05 ~s and the velocity of the…
NEET UG 2008 — Physics Waves & Oscillations
Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?
Held on 30 Apr 2008 · Verified 9 Jul 2026.
Options
- A
3π
- B
32π
- C
π
- D
6π
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