Key Idea : Velocity is the time derivative of displacement. Writing the given equation of a point performing SHM x=asin(ωt+6π) Differentiating Eq. (i), w.r.t. time, we obtain y=dtdx=aωcos(ωt+6π) It is given that y=2aω, so that or 2aω=aωcos(ωt+6π) 21=cos(ωt+6π) or cos3π=cos(ωt+6π) or ⇒or ωt+6π=3πωt=6πt=6ωπ=6×2ππ×T=12T Thus, at 12T velocity of the point will be equal to half of its maximum velocity.