Reverberation Time T=AS0⋅61V Where V= Volume of room in cubic metre A= Average coefficient of the room S= Total surface area of room Then, T∝SV or T2T1=(V2V1)(S1S2)=(8VV)(545)=21∴T2=2T1=2×1=2sec.(∵T1=1sec)
The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double…
NEET UG 2006 — Physics Waves & Oscillations
The time of reverberation of a room A is one second. What will be the time (in seconds) of reverberation of a room, having all the dimensions double of those of room A ?
Held on 30 Apr 2006 · Verified 9 Jul 2026.
Options
- A
1
- B
2
- C
4
- D
21
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