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The phase difference between two waves represented by … wherexis expressed in metres andt is expressed in seconds is approximately

NEET UG 2004 — Physics Waves & Oscillations

2004mcqeasy

The phase difference between two waves represented by y1=10−6sin⁡[100t+(x/50)+0.5]my1=10−6cos⁡[100t+(x/50)]m\begin{aligned} & y_1=10^{-6} \sin [100 t+(x / 50)+0.5] \mathrm{m} \\ & y_1=10^{-6} \cos [100 t+(x / 50)] \mathrm{m} \end{aligned}​y1​=10−6sin[100t+(x/50)+0.5]my1​=10−6cos[100t+(x/50)]m​ where xxx is expressed in metres and ttt is expressed in seconds is approximately

Official previous-year question

Held on 30 Apr 2004 · Verified 9 Jul 2026.

Options

  1. A

    1.07 radians

  2. B

    2.07 radians

  3. C

    0.5 radians

  4. D

    1.5 radians

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