The K.E. of pendulum =K.E.=21K(a2−y2) and P.E. of pendulum =21KY2 when y=0 (mean position) K.E. is maximum and PE is 0 . When y=0, K.E. is 0 and P.E. is maximum. ∴ The displacement between position of maximum potential energy and maximum kinetic energy is ±a.
Displacement between the maximum potential energy (P.E.) position and the maximum energy (K.E.) position for a particle executing simple harmonic…
NEET UG 2002 — Physics Waves & Oscillations
Displacement between the maximum potential energy (P.E.) position and the maximum energy (K.E.) position for a particle executing simple harmonic motion is:
Held on 30 Apr 2002 · Verified 9 Jul 2026.
Options
- A
±2a
- B
±a
- C
±2a
- D
- 1
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