H2+1/2O2→H2O 2 g16 g18 g 10 gH2 required O2=80 which is not present 64 g O2 required 8 g of H2 and H2 left =2 g. Thus, O2 is the limiting reactant and H2 is excess reactant. Hence, H2O formed from 64 of O2 =1618×64=72 g=1872 mole=4 mole
10 ~g of hydrogen and 64 ~g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be -
NEET UG 2009 — Chemistry Physical Chemistry
10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be -
Held on 30 Apr 2009 · Verified 9 Jul 2026.
Options
- A
1 mol
- B
2 mol
- C
3 mol
- D
4 mol
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