For log3log5(⋅) we need log5(⋅)>0
So 7−log2(x2−10x+85)>1, giving x2−10x+85<64
(x−3)(x−7)<0
⇒3<x<7.
For sin−1(17−x3x−7) we need ∣3x−7∣≤∣17−x∣
i.e, (x−6)(x+5)≤0⇒−5≤x≤6.
Intersection: (3,6], so α=3,β=6.
α+β=9
JEE Main 2026 — Mathematics Algebra
Let the domain of the function f(x)=log3log5(7−log2(x2−10x+85))+sin−1(17−x3x−7) be (α,β]. Then α+β is equal to :
Held on 22 Jan 2026 · Verified 6 Jul 2026.
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