For log3log5(⋅) we need log5(⋅)>0
So 7−log2(x2−10x+85)>1, giving x2−10x+85<64
(x−3)(x−7)<0
⇒3<x<7.
For sin−1(17−x3x−7) we need ∣3x−7∣≤∣17−x∣
i.e, (x−6)(x+5)≤0⇒−5≤x≤6.
Intersection: (3,6], so α=3,β=6.
α+β=9
JEE Main 2026 — Mathematics Algebra
Let the domain of the function f(x)=log3log5(7−log2(x2−10x+85))+sin−1(17−x3x−7) be (α,β]. Then α+β is equal to :
Held on 22 Jan 2026 · Verified 6 Jul 2026.
9
10
12
8
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
The number of elements in the set $S = \left\{(r, k) : k \in \mathbb{Z} \text{ and } {}^{36}C_{r+1} = \dfrac{6\left({}^{35}C_r\right)}{(k^2 - 3)}\right\}$, is :
Suppose $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are in A.P. and $\mathrm{a}^{2}, 2 \mathrm{~b}^{2}, \mathrm{c}^{2}$ are in G.P. If $\mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\mathrm{a}+\mathrm{b}+\mathrm{c}=1$, then $9\left(\mathrm{a}^{2}+\mathrm{b}^{2}+\mathrm{c}^{2}\right)$ is equal to $\_\_\_\_$ .
Let $S=\left\{z \in \mathbb{C}: 4 z^{2}+\bar{z}=0\right\}$. Then $\sum_{z \in S}|z|^{2}$ is equal to:
Let $S=\{z: 3 \leqslant|2 z-3(1+i)| \leqslant 7\}$ be a set of complex numbers. Then $\min _{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to :
Let $A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix}$ and $B = [b_{ij}]$, $1 \leq i, j \leq 3$. If $B = A^{99} - I$, then the value of $\dfrac{b_{31} - b_{21}}{b_{32}}$ is :
Work through every JEE Main Algebra PYQ, year by year.