Sn=αn2+βn⇒an=Sn−Sn−1=α(2n−1)+β for n≥1.
a10=19α+β=59 ... (i)
a6=11α+β, a1=α+β.
a6=7a1⇒11α+β=7α+7β⇒4α=6β⇒α=23β ... (ii)
Substituting (ii) in (i): 19⋅23β+β=59⇒259β=59⇒β=2, α=3.
α+β=5.
JEE Main 2026 — Mathematics Algebra
Let k=1∑nak=αn2+βn. If a10=59 and a6=7a1, then α+β is equal to
Held on 23 Jan 2026 · Verified 6 Jul 2026.
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