Common difference d=a2−a1=−3/4.
an=a1+(n−1)(−3/4)=a1/4
⇒ 3a1/4=3(n−1)/4
⇒a1=n−1.
Sn=2n(a1+an)=2n⋅45a1=85na1=2525
na1=420.
Since a1=n−1: n(n−1)=420
⇒n=21,a1=20.
i=1∑17ai=217(2⋅20+16⋅(−3/4))
=217(40−12)=17×14=238
JEE Main 2026 — Mathematics Algebra
Consider an A.P.: a1,a2,…,an;a1>0. If a2−a1=4−3,an=41a1, and i=1∑nai=2525, then i=1∑17ai is equal to
Held on 24 Jan 2026 · Verified 6 Jul 2026.
136
476
238
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