Let bn=an−n22.
bn+1=21an+n2(n+1)2n2−2n−1−(n+1)22.
Simplifying: bn+1=21bn+n2(n+1)2(n+1)2+n2−2n−1−2n2=21bn.
So bn is GP with ratio 21.
b1=1−2=−1, so bn=−(21)n−1.
n=1∑∞bn=−1−211=−2.
n=1∑∞(an−n22)=2.
JEE Main 2026 — Mathematics Algebra
Let a1=1 and for n⩾1,an+1=21an+n2(n+1)2n2−2n−1. Then n=1∑∞(an−n22) is equal to ____.
Held on 21 Jan 2026 · Verified 6 Jul 2026.
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